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Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined) c-table Tennis Game 2

, for example, the rule of "balance" (The winning player have to is at least, points ahead to win a set) have no power within the present problem.Test instructions: Test instructions good fan, do the problem by enumerating test instructions.The title says two people are playing, each game has a lot of rounds, each round of winning players can get a point. If someone's score is k in a match, the game ends and a game is re-opened.Now give the two people a total score, a, B, ask you whether the sco

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined)

case of the root of 1 and O (1) Move the root#include #includeusing namespaceStd;inlineintRead () {intXCharC; while((C=getchar ()) '0'|| C>'9'); for(x=c-'0';(C=getchar ()) >='0'c'9';) x= (x3) + (x1) +c-'0'; returnx;}#defineMN 200000structedge{intNx,t;} e[mn*2+5];inth[mn+5

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + Div. 2 combined) E. Tree folding

read his blog, and tell it in detail.1#include 2 3 using namespacestd;4 5 #defineMP Make_pair6 #definePB push_back7typedefLong LongLL;8typedef pairint,int>PII;9 Const Doubleeps=1e-8;Ten Const DoublePi=acos (-1.0); One Const intk=2e5+7; A Const intmod=1e9+7; - - intn,mx; thevectorint>Mp[k]; - - intDfsintXintf) - { + inta[3],num=0; - for(intI=0; I) +

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined) B

". ExamplesinputAbacabaOutputYESinputJinotegaOutputNONoteIn the first sample case, one possible list of identifiers would is "numberstring number character number string numb Er ". Here are Kostya would obfuscate the program: Replace all occurences of number with A, the result would is "a string a character a string a", Replace all occurences of string with B, the result would is "a B a character a b a", Replace all occurences of character with C, the result would is "a B

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined) A

home or contestSolution: Since the departure from home will return, then we just have to compare the number of times the odd-and-even sex is on the line, the numbers are at home, odd is not back1#include 2 using namespacestd;3 intN;4 Chars1[ $],s2[ $];5 intMain ()6 {7 intans=0;8Cin>>N;9scanf"%s", S1);Ten for(intI=0; i) One { Ascanf"%s", S2); - if(STRSTR (S2,S1)! =NULL) - { thea

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined)

[f[i]]=F[i]; G[i]=F[i]; } intCNT =1; for(inti =1; I ) if(H[i]) {Id[h[i]]=CNT; H[CNT]=H[i]; CNT++; } for(inti =1; I ) G[i]=Id[g[i]]; for(inti =1; I ) if(G[h[i]]! =i) {puts ("-1"); return 0; } for(inti =1; I ) if(H[g[i]]! =F[i]) {Puts ("-1"); return 0; } printf ("%d\n", CNT-1); for(inti =1; I ) printf ("%d", G[i]); Puts (""); for(inti =1; I ) printf ("%d", H[i]); Puts ("");

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined)

  A question, water problem, judge all points is not into degrees and out of the same can be.Question B, test instructions understand is water problem.Question C. The other party must win at least one of the points after the score mod K. This method can be used to judge.Problem d, construction problem, not = =.E, test instructions is the choice of a node each time, the two sons of the same length of the chain to merge into a new chain of the same length. Ask if the end can be a straight chain, i

Codeforces Round #397 by Kaspersky Lab and Barcelona bootcamp (div. 1 + div. 2 combined) D. Artsem and Saunders

print mnumbers h(1),?...,? H(m). If There is several correct answers, you could output any of the them. It is guaranteed that if a valid answer exists and then there was an answer satisfying the above restrictions.Examplesinput31 2 3Output31 2 31 2 3input32 2 2Output11 1 12input22 1Output-1Idea: The person with

C ++ pure virtual function virtual = 0

C ++ pure virtual function virtual = 0 Reference: http://hi.baidu.com/cunlin/blog/item/d82b160102e0e4037aec2ccb.html (Baidu space) ========================================================== ====================================== Pure virtual functions in C ++ A function declaration in C ++ is called a pur

In oracle, the pure number in the updated bytes data is set to a fixed length (0 on the left)

The error in the previous requirement document resulted in the fact that the originally three-digit number was not fixed, and later it was found that the requirement document had mistaken the requirement. The pure number in this field must be three digits.This field currently has thousands of rows of data, including a combination of letters, numbers, and numbers. The number of digits is not fixed. therefore, you can only write a script to update data,

[Clojure] A Room-escape game, playing with Telnet and Pure-text Commands-part 2

): continue (Atom true) : Last-action (Atom [])}1) Player-objects:all the objects related to the game of the Player;2) starting-room:the ID of the "the" player starts with;3) Current-status:location and possessed items of the player;4) Visible:the Collection of Visible objects in this game based on how the player played the game;5) Win:indicate If the player has won the game;6) Continue:indicate If the player wants to Continue the

DIV+CSS (2): pure div+css made beautiful click button and Close button

Pure div+css made beautiful click button and Close button, click the Click button also has effect. These are not pictures.Three points worth noting:1. Among them, the main use of rotate. It allows the text to rotate the angle2. There are radius, do the round corner dedicated, very useful properties. For people like me save time for drawing.Transition of CSS3 in the 3.W3C standard this is kind of description: "CSS transition allows CSS property values

Monster Farm 2 Modify log 5-bliss Pure Land

Next, Monster Farm 2 change log 4-the eve of the battleBGM, recently the pure bliss of the B station.In the previous article, we succeeded in finding the location of the monster Race ID and the sub-race ID stored in memory from the data read from the CD.By modifying the memory location, it is possible to directly determine the last spawn, including special monsters, that can be generated directly.Next we'll

Split natural number: pure while implementation (Part 2

that the lower and upper bounds are useless, look at my writing to know: function Main (m, N, Min, max) { var array = new Array (n); var i = 0;   var write = function () { Console.log (m + ' = ' + array.join (' + ')); };      var scan = function () { if (scan.start) { Scan.start = false; scan.sum = 0;    } Scan.sum + = Array[i]; Return (Array[i] > Array[n-1]-

Algorithm template--and check set 2 (Support fast Instant query this connected block content, pure original!) )

finally static global processing, the difference is not too much, this will be slightly faster, the traditional program code slightly less(PS: It is worth noting that this new data structure in the tens of thousands of two numbers in the same block of the case, you must avoid the same chain end-to-end lead to produce a ring!!! This program 41 line continue there is reflected. Merge block statements such as C[x]:=y and merge (x, Y) operations are ordered, and the order must be consistent and do

13th Week "Project 2-pure virtual function in the shape class family"

Description of the problem:Write a program. Defines the abstract base class shape, which derives 3 derived classes, Circle (circle), Rectangle (Rectangle), Triangle (triangle). Use the main () function such as the following. Find the area and the number of geometry defined.int main () { Circle C1 (12.6), C2 (4.9);//Create Circle Class object c1,c2 with radius Rectangle R1 (4.5,8.4), R2 (5.0,2.5);// Establish the Rectangle class object R1,R2, the length of the rectangle, the width Triang

13th Week Item 2-pure virtual functions in the Shape class family

Write a program that defines the abstract base class shape, derived from it by 3 derived classes, Circle (circle), Rectangle (Rectangle), Triangle (triangle). Use the following main () function to find the area and the number of geometry defined.int main () { Circle C1 (12.6), C2 (4.9),//Create Circle Class object C1,c2, parameters are circle radius Rectangle R1 (4.5,8.4), R2 (5.0,2.5);// Establish the Rectangle class object R1,R2, the parameters are rectangle length, width Triangle T1

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